Question

3. Prove that the following are irrational
1underrootof2solution​

Answer 1

Answer:

Let us prove that √5 is an irrational number, by using the contradiction method. So, say that √5 is a rational number can be expressed in the form of pq, where q ≠0. So, let √5 equals pq. Where p, q are co-prime integers i.e. they do not have any common factor except '1'.

Step-by-step explanation:

We know that R is uncountable, whereas Q is countable. If the set of all irrational numbers were countable, then R would be the union of two countable sets, hence countable. Thus the set of all irrational numbers is uncountable.

Answer 2

Step-by-step explanation:

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