Question

3. Prove that the following are irrationals:
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Answer 1

you can prove these by contradiction

1/ underoot 2 - a/ b and integer, co prime

a/b - underoot 2

here a/b is rational but underoot 2 is not , so our contradiction is wrong

7 underoot 5 - a/b

then, 1/7√5 - a/b

here, a/ b are rational but 7√5 is not hence we contradict wrong

6+√2 - a/b

1/6+√2 - a/b

here, √2 is not rational

Answer 2

Answer:

1÷√2=0.70710678116

Step-by-step explanation:

If you will divide 1÷√2

Then you will got The answer 0.70710678116