Question

3. prove that the parallelogoun circumsepibing circle is a rhombusa
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Answer 1

Question :

To prove that the parallelogoun circumsepibing circle is a rhombusa.

$\mid\rm\underline\green{Given}\mid$

A circle with centre O.

A parallelogram ABCD touching the circle at points P,Q,R and S.

$\mid\rm\underline\blue{To, prove}\mid$ - ABCD is a rhombus.

$\mid\rm\underline\red{Proof}\mid$

A rhombus is a parallelogram with all sides equal,

So, we have to prove all sides are equal.

In parallelogram ABCD,

AB - CD & AD - BC (Opposite sides of parallelogram are equal )

Hence Proved.