Question

3. Prove that the product of two consecutive positive integers is divisible by 2.​

Answer 1

Answer:

divisible by 2

Step-by-step explanation:

here is your answer

hope it helps you

mark me as brainliest

Answer 2

Step-by-step explanation:

To prove: product of two consicutive positice integer is divisible by two.

Proof:

Any even number is divisible by two.

Suppose the two consecutives numbers are (x) and (x + 1)

so the product of consecutives numbers = (x)(x + 1)

(i) for an even number

Let x = 2k,

product = (2k)(2k + 1)

From the above equation it is clear that the product is

divisible by two.

(ii) for an odd number

Let x = 2k + 1

product = (2k + 1){(2k + 1) + 1}

= (2k + 1)(2k + 2)

= 2(2k^2+3k+1)

From the above equation it is clwar that it is divisible

by two.

Hence proved.