3. prove that the tangents brown a perpendicula, at the point
of contact to the tangent to a corto passes through the
centro
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Answer:
Given: Let us assume a circle with centre O & AB be the tangent intersecting circle at point P.
To prove: OP⊥ AB
Proof: We know that
Tangent of circle is $$\perpendicular to radius at point of contact.
Hence, OP⊥AB(Tangent at any point of circle is perpendicular to the radius through point of contact)
So, ∠OPB=90
o
……….(1)
Now, lets assume some point x, such that XP⊥AB
Hence, ∠XPB=90
o
……….(2)
From (1) & (2)
∠OPB=angleXPB=90
o
which is possible only if line XP passes through.
Hence, perpendicular to tangent passes through centre.
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