Question

3
Q no.2
A 21m deep well with diameter 6m is dig and the
earth from the digging is evenly spread to from a
platform 27m x 11m. Find the height of the
platform.​

Answer 1

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Answer 2

ANSWER

Given,depth of well=21m

Radius of well=6/2=3

Volume of earth dugout from the well=πr^2h

22/7×3×3×21

=594m^3

Let the height of the platform=h m.

Volume of platform=volume of earth dugout

27×11×h=594

h=594/27×11=594/297

so height of the platform,h=2m.