Question

[3]
Q34.
In class 10 A, there are 20 boys and 20 girls. In 10 B, there are 15 boys and 25 girls. One student is to be selected from each
class.
(1) What is the probability of both being girls?
(ii) What is the probability of both being boys?
(iii) What is the probability of one boy and one girl?​

Answer 1

Answer:

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Answer 2

(1) Probability of both being girls = $\frac{5}{16}$ or 0.3125

(2) probability of both being boys = $\frac{3}{16}$ or 0.1875

(3) probability of one boy and one girl = $\frac{63}{256}$ or 0.246

Step-by-step explanation:

In class 10 A there are total boys and girls = 20 + 20

                                                                      = 40

In class 10 B there are total boys and girls = 15 + 25

                                                                      = 40

$p=\frac{\text{favorable outcome}}{\text{total outcome}}$

(1) The probability of selecting girl from 10 A p₁ = $\frac{20}{40}=\frac{1}{2}$

  The probability of selecting girl from 10 B p₂ = $\frac{25}{40}=\frac{5}{8}$

Probability =  p₁ × p₂

                  = $\frac{1}{2}\times\frac{5}{8}$

                  = $\frac{5}{16}$ = 0.3125

(2) The probability of selecting boy from 10 A p₁ = $\frac{20}{40}=\frac{1}{2}$

    The probability of selecting boy from 10 B p₂ = $\frac{15}{40}=\frac{3}{8}$

Probability = $\frac{1}{2}\times \frac{3}{8}$

                  = $\frac{3}{16}$ = 0.1875

(3) The probability of selecting one boy p₁ = $\frac{35}{80}=\frac{7}{16}$

     The probability of selecting one girl p₂ = $\frac{45}{80}=\frac{9}{16}$

Probability = $\frac{7}{16}\times \frac{9}{16}$

                  = $\frac{63}{256}$ =  0.24609375

(1) Probability of both being girls = $\frac{5}{16}$ or 0.3125

(2) probability of both being boys = $\frac{3}{16}$ or 0.1875

(3) probability of one boy and one girl = $\frac{63}{256}$ or 0.246

Learn more about probability : https://brainly.in/question/15193759