3(R+10)+200=236
solve this
Answers
Answer:
3R+30=236-200
3R=36-30
R=6/3
R=2
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Answer:
How to solve your problem
3
(
+
1
0
)
+
2
0
0
=
2
3
6
3(r+10)+200=236
3(r+10)+200=236
Solve
1
Distribute
3
(
+
1
0
)
+
2
0
0
=
2
3
6
{\color{#c92786}{3(r+10)}}+200=236
3(r+10)+200=236
3
+
3
0
+
2
0
0
=
2
3
6
{\color{#c92786}{3r+30}}+200=236
3r+30+200=236
2
Add the numbers
3
+
3
0
+
2
0
0
=
2
3
6
3r+{\color{#c92786}{30}}+{\color{#c92786}{200}}=236
3r+30+200=236
3
+
2
3
0
=
2
3
6
3r+{\color{#c92786}{230}}=236
3r+230=236
3
Subtract
2
3
0
230
230
from both sides of the equation
3
+
2
3
0
=
2
3
6
3r+230=236
3r+230=236
3
+
2
3
0
−
2
3
0
=
2
3
6
−
2
3
0
3r+230{\color{#c92786}{-230}}=236{\color{#c92786}{-230}}
3r+230−230=236−230
4
Simplify
Subtract the numbers
Subtract the numbers
3
=
6
3r=6
3r=6
5
Divide both sides of the equation by the same term
3
=
6
3r=6
3r=6
3
3
=
6
3
\frac{3r}{{\color{#c92786}{3}}}=\frac{6}{{\color{#c92786}{3}}}
33r=36
6
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
2
r=2
r=2
Solution
=
2