3. Raju’s father is 7 times as old as Raju. After 10 years he will be three times as old as his son. Find their present ages.
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let raju's age be x, then his father's age will be 7x.
after 10 years, raju's age will be x+10 and his father's age will be 7x+10.
after 10 years raju's father will be his 3 times, i.e. :
7x+10= 3(x+10)
=7x+10= 3x+30
=7x-3x=30-10
=4x=20
=x=20/4
=5
therefore raju's age is 5 years and his father's age is 7x i.e. 7*5= 35
after 10 years, raju's age will be x+10 and his father's age will be 7x+10.
after 10 years raju's father will be his 3 times, i.e. :
7x+10= 3(x+10)
=7x+10= 3x+30
=7x-3x=30-10
=4x=20
=x=20/4
=5
therefore raju's age is 5 years and his father's age is 7x i.e. 7*5= 35
Answered by
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Answer:
let raju's age be x, then his father's age will be 7x.
after 10 years, raju's age will be x+10 and his father's age will be 7x+10.
after 10 years raju's father will be his 3 times, i.e. :
7x+10= 3(x+10)
=7x+10= 3x+30
=7x-3x=30-10
=4x=20
=x=20/4
=5
therefore raju's age is 5 years and his father's age is 7x i.e. 7*5= 35
hope it is correct
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