Question

3. Raju sold a bicycle to Amit at/8% profit. Amit
repaired it spending + 54. Then he sold the
bicycle to Nikhil for 1134 with no loss and
no profit. Find the cost price of the bicycle for
which Raju purchased it.​

Answer 1

Answer:

Let the cost price at which Raju purchased be 'x'.

It is given that he sold to Amit for a profit of 8%.

$\implies \boxed{x + \dfrac{8}{100} \times x = \text{Cost Price for Amit}}$

⇒ 1.08x = Cost Price for Amit   ...(i)

Now Amit spends Rs. 54 on repairing and sells it to Nikhil for Rs. 1134 gaining no profit or loss. Therefore this means that, Amit sells it at the same cost with which he bought just by adding the additional repair expense.

⇒ Cost Price for Amit = Selling price of Nikhil - Repair Charges

⇒ Cost Price for Amit = 1134 - 54

⇒ Cost Price for Amit = Rs. 1080   ...(ii)

We know that Cost price of Amit = 1.08x (from (i))

Equating (i) and (ii) we get:

⇒ 1.08x = 1080

⇒ x = (1080/1.08)

⇒ x = 1000

Hence the cost price for which Raju purchased the cycle was Rs. 1000

Answer 2

Step-by-step explanation:

Given :

Raju sold bicycle Amit 8%

Amit repairing + 54

He Sold Nikhil rs 1134 no loss and no profit

Find :

Cost Price Of Bicycle Raju Purchased.

Solution :

Let the cost price of bicycle be Rs X

Since Raju sold the bicycle at 8 % profit to Amit

Therefore Selling price of Raju = X + 8% of X

Selling price of Raju = X + 8/100 × X

Selling price of Raju = 108x / 100

Since , Amit Spent rs 54 on repairing the bicycle and them sold it to Nikhil Rs 1134 at no loss and no profit

Therefore , Selling price of bicycle + repairing cost = Rs 1134

Therefore , 108x / 100 + 54 = 1134

108x / 100 = 1134 - 54 ( Transposing 54 to RHS Side )

108x / 100 = 1080

108x = 1080 × 100 ( Transposing 100 to RHS Side )

108x = 108000

X = 108000/108 ( Divide 108 by 108000)

X = 1000

The Cost Price Of Bicycle at which Raju purchased Rs 1000