Question

3. Ram has 3 times as many 2 coins as he has 5 coins. If he has in all a sum of 77, how many coins
of 2 does he have?
4. The sum of three consecutive numbers is 156. Find the number which is a multiple of 13 out of these
numbers.
ned​

Answer 1

let the money be =x

let the 2rupees coins be =2x

let the 5 rupees count be =5x

2x+5x=77

7x=77

x=11

then multiply 11 with two u will get 22

Answer 2

Hey mate,

Let Ram has "x" five-rupee coins. Then he will have 3x two-rupees coins. We are given,

5x+2(3)x=77

5x+6x=77

11x=77

x=77/11=7

So Bansi has 7 five rupees coins and 21 two rupees coins.

4.

Let's take one integer as x.

We know that, the consecutive one would obviously be x+1 and x+2

So the three numbers are x, x+1 and x+2.

Now, We know that they sum up to 156. Hence,

x+ x+1+ x+2=156

3x+3=156

3x=153

x=51

So the Consecutive integers will be 51, 52, 53 (x+1 and x+2)

Now that we have to find a number 'divisible' by 13. It is easy, We already know 52 is exactly divisibly by 13.

The answer is 52.

(Image solution is attached of the 4th question.)

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