Math, asked by rikkin, 1 year ago

3 rd one how to solve it

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Answered by 01Ashu111
1
Hi friend,
Given: ABC is a triangle in which AB=AC. P is any point in the interior of the triangle such that angle ABP=ACP.

To Prove: AP bisects angle BAC

Proof: 

In ∆APB and ∆APC,

AB = AC [given]

angleABP = angle ACP [given]

AP = AP [common]

∴tr. APB and tr. APC (by SAS)

also, angle PAB = angle PAC [corresponding angles of congruent triangles]


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