Question

3.
Red light of wavelength 6500A from a distant source falls on a slit 0.50 mm wide. What is the distance between
the first two dark bands on each side of the central bright of the diffraction pattern observed on a screen
placed 1.8 m from the slit.​

Answer 1

Answer:

Single slit experiment. 

Formula for fringe width = λ D / d

      slit width  d = 0.001 m = 1mm ,  

       λ = 600 nm  ,  D = screen distance = 2m

 

So fringe width = 600 nm * 2m /0.001 m   = 1.2 mm

DIstance between two dark fringes which are on either side of the central bright fringe = 2 * 1.2 mm = 2.4 mm

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