3 register of 2ohm,3ohm and 5 ohm are connected in the electric circuit calculate 1 maximum effective resistance 2 minimum effective resistance
Answers
Answered by
74
hey frnd here is ur ans
the maximum resistance can be found by adding all the resistance that is placing them in series
so Rs=R1+R2+R3=2+3+5=10ohm
minimum effective resistance is obtained if we make parallel combinations
so 1/Rp=1/R1+1/R2+1/R3=1/2+1/3+1/5=6/5
so Rp=5/6=0.83ohm
now if we can keep two of the larger resistors in parallel and the smaller in series
1/Rp=1/R2+1/R3=1/3+1/5=16/30
so Rp=30/16=1.875ohm
now in series
Rs=R1+1.875 ohm =2+1.875=3.875 ohm
hope it helps
the maximum resistance can be found by adding all the resistance that is placing them in series
so Rs=R1+R2+R3=2+3+5=10ohm
minimum effective resistance is obtained if we make parallel combinations
so 1/Rp=1/R1+1/R2+1/R3=1/2+1/3+1/5=6/5
so Rp=5/6=0.83ohm
now if we can keep two of the larger resistors in parallel and the smaller in series
1/Rp=1/R2+1/R3=1/3+1/5=16/30
so Rp=30/16=1.875ohm
now in series
Rs=R1+1.875 ohm =2+1.875=3.875 ohm
hope it helps
Answered by
28
Answer:
Minimum= 1.03 Ohm
Maximum= 10 Ohm
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