Question

3. Rene is 6 years older than her younger sister. After 10 years, the sum of
their ages will be 50 years. Find their present ages​

Answer 1

Answer:

Step-by-step explanation:

Let the present age of Rene's younger sister be x

The present age of Rene be x + 6

After 10 years the sum of their ages = 50 years

A/q,

=> [(x + 6) + 10] + [x + 10]  = 50 

=> [(x + 16) + (x + 10)] = 50

=> 2x + 26 = 50

=> 2(x + 13) = 50

=> x + 13 = 50/2

=> x + 13 = 25

=> x = 25 - 13

=> x = 12

The age of Rene's younger sister = x = 12 years

The age of Rene = x + 6 = 18 years

Answer 2

Given :

Rene is 6 years older than her younger sister.

After 10 years the sum of there ages will be 50 years.

To find :

Their present ages =?

Step-by-step explanation :

The present age of Rene's younger Sister be, x.

Then, the present age of Rene's be, x + 6.

It is Given that,

After 10 years the sum of there ages will be 50 years .

So,

After 10 years Rene's age will be = x + 10

After 10 years Rene's younger sister age will be = x + 6 + 10.

According to the question,

[(x + 6) + 10] + [x + 10] = 50

[(x + 16) + (x + 10)] = 50

2x + 26 = 50

2(x + 13) = 50

x + 13 = 50/2

x + 13 = 25

x = 25 - 13

x = 12

Therefore, We got the value of, x = 12.

Hence,

The age of Rene's younger sister = x = 12 years

The age of Rene = x + 6 = 18 years

Step-by-step explanation: