Question

3 resistors of resistances 5ohm 3ohm 2ohm are connected in series with 10volt battery. Calculate their effective resistance and current flowing through the circuit

Answer 1

Effective resistance = 10 Ω

Current through the circuit = 1 A

Explanation:

given three resistances in series

R₁ = 5 Ω

R₂ = 3 Ω

R₃ = 2 Ω

=> Resistance in series = R₁ + R₂ + R₃

=> R = 5+3+2

=> R = 10 Ω

According to Ohm's Law   V= I R

where, V= applied voltage

             I = current flowing

             R = resistance

(In series current will be same through all the elements)

=> $I = \frac{V}{R}$

=> $I = \frac{10}{10}$

=> $I = 1 A$

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Answer 2

Answer:

the answer is 10...........