Question

3 root 12, / 6root 27 =?​

Answer 1

Answer:

Given

$3 \sqrt{12} \div 6 \sqrt{27 } = 3 \sqrt{4 \times 3} \div 6 \sqrt{9 \times 3}$

$= 3 \times 2 \sqrt{3} \div 6 \times 3 \sqrt{3}$

$6 \sqrt{3} \div 18 \sqrt{3}$

$\sqrt{3} \: is \: canclled \:$

$1 \div 3$

I hope it is the correct answer.