3 + root 2 upon 3 minus root 2 is equal to a + b root to solve this equation
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Answer:
3+√2/3-√2=a+b√2
Lhs
=3+√2 /3-√2 * 3+√2 /3+√2
=(3+√2)^2 /(3)^2 -(√2)^2
= 9+2+6√2 / 9-2
= 11+6√2 / 7
now comparing with a+b√2
a= 11/7and
b= 6√2/7
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