Question

3 root 2 x square - 5 x minus root 2 is equal to zero

Answer 1

Answer:

$x = \frac{1}{\sqrt{2}}\: Or \: x = \frac{\sqrt{2}}{3}$

Step-by-step explanation:

$Given \: quadratic \: equation\\3\sqrt{2}x^{2}-5x-\sqrt{2}=0$

/* Splitting the middle term, we have

$\implies 3\sqrt{2}x^{2}-3x-2x-\sqrt{2}=0$

$\implies 3\sqrt{2}x^{2}-3x-\sqrt{2}\times \sqrt{2}x-\sqrt{2}=0$

$\implies 3x(\sqrt{2}x-1)-\sqrt{2}(\sqrt{2}x-1)=0$

$\implies (\sqrt{2}x-1)(3x-\sqrt{2})=0$

$\implies (\sqrt{2}x-1)=0 \: Or \:(3x-\sqrt{2})=0$

$\implies \sqrt{2}x=1 \: Or \:3x=\sqrt{2}$

$\implies x = \frac{1}{\sqrt{2}}\: Or \: x = \frac{\sqrt{2}}{3}$

Therefore,

$x = \frac{1}{\sqrt{2}}\: Or \: x = \frac{\sqrt{2}}{3}$

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Answer 2

Answer:

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Step-by-step explanation:

3√2x²-3x-2x-√2=0

3x(√2-1) -√2x(√2x-1)

(3x-√2). (√3x-1)

x=√2/3. x=1/√2.

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