Question

3 Root 3 + 2 root 27+ 7/root3

Answer 1

Answer:

$3\sqrt{3}+2\sqrt{27}+\frac{7}{\sqrt{3}}=\frac{34\sqrt{3}}{3}$

Step-by-step explanation:

$Given \\ 3\sqrt{3}+2\sqrt{27}+\frac{7}{\sqrt{3}}\\=3\sqrt{3}+2\sqrt{(3\times 3\times 3)}+\frac{7\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}\\=3\sqrt{3}+6\sqrt{3}+\frac{7\sqrt{3}}{3}\\=\frac{9\sqrt{3}+18\sqrt{3}+7\sqrt{3}}{3}\\=\frac{(9+18+7)\sqrt{3}}{3}\\=\frac{34\sqrt{3}}{3}$

Therefore,

$3\sqrt{3}+2\sqrt{27}+\frac{7}{\sqrt{3}}=\frac{34\sqrt{3}}{3}$

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Answer 2

Answer:

this is the answer..............