Question

3 root 3 + 2 root 27 + 7 upon root 3​

Answer 1

Step-by-step explanation:

underoot 27 is cube root of 3

so doing its square it gives 3underoot3

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

$\sf{ =3 \sqrt{3} + 2 \sqrt{27} + \frac{7}{ \sqrt{3} } }$

$\sf{ =3 \sqrt{3} + 2 \times 3 \sqrt{3} + \frac{7}{ \sqrt{3} } }$

$\sf{ = 3\sqrt{3} + 6 \sqrt{3} + \frac{7 \sqrt{3} }{3} }$

$\sf{ = \sqrt{3} \bigg(3 + 6 + \frac{7}{3} \bigg) }$

$\sf{ = \sqrt{3} \bigg(9 + \frac{7}{3} \bigg) }$

$\sf{ = \sqrt{3} \times \frac{34}{3} }$

$= \boxed{ \sf{ \frac{34}{3} \sqrt{3} } }\: \: \: \bf{ Ans.}$