3/ root 3 - root 2 = a root 3 - b root 2
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Hiii friend,
3/✓3-✓2 = A✓3-B✓2
LHS = 3/✓3-✓2
Rationalizing the denominator
=> 3/✓3-✓2 × ✓3+✓2/✓3+✓2
=> 3(✓3+✓2)/(✓3-✓2)(✓3+✓2)
=> 3✓3+3✓2/(✓3)² - (✓2)²
=> 3✓3+3✓2/3-2
=> 3✓3+3✓2/1
=> 3✓3+3✓2
RHS = A✓3+B✓2
LHS = RHS
3✓3+3✓2 = A✓3+B✓2
Hence,
A = 3 and B = 3
3/✓3-✓2 = A✓3-B✓2
LHS = 3/✓3-✓2
Rationalizing the denominator
=> 3/✓3-✓2 × ✓3+✓2/✓3+✓2
=> 3(✓3+✓2)/(✓3-✓2)(✓3+✓2)
=> 3✓3+3✓2/(✓3)² - (✓2)²
=> 3✓3+3✓2/3-2
=> 3✓3+3✓2/1
=> 3✓3+3✓2
RHS = A✓3+B✓2
LHS = RHS
3✓3+3✓2 = A✓3+B✓2
Hence,
A = 3 and B = 3
oceanphotocollection:
i am sorry but its actually minus . so how to equate it
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