Question

3/ root 3 - root 2 + root 5

Answer 1

Answer:

$3 \div \sqrt{3} - \sqrt{2} + \sqrt{5}$

Apply congugate

$3 \times \sqrt{3} \div \sqrt{3} \times \sqrt{3}$

$3 \sqrt{3} \div 3$

3/3 are cancle out

$\sqrt{3} - \sqrt{2} + \sqrt{5}$

$\sqrt{3 - 2 + 5}$

$\sqrt{1 + 5}$

$\sqrt{6}$

Answer