Question

3× (root 3- root 2- root 5)/2*root 6

Answer 1

Solution:

[3(√3-√2-√5)/2√6]

Multiply numerator and denominator by √6 , we get

= [3√6(√3-√2-√5)]/[2√6×√6]

= [3√6(√3-√2-√5)]/2×6

= [√6(√3-√2-√5)]/4

= [3√2-2√3-√30]/4

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