Question

3+root 5/3-root 3 maths grade 9

Answer 1

$= \frac{3 + \sqrt{5} }{3 - \sqrt{3} } \times \frac{3 + \sqrt{3} }{3 + \sqrt{3} } \\ = \frac{3(3 + \sqrt{3} ) + \sqrt{5}(3 + \sqrt{3)} }{ {(3)}^{2} - { (\sqrt{3} )}^{2} } \\ = \frac{9 + 3 \sqrt{3 } + 3 \sqrt{5} + \sqrt{15} }{9 - 3} \\ = \frac{3 \sqrt{3} + 3 \sqrt{5} + \sqrt{15} + 9}{6}$

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