Question

3 -root 5 prove that is irrational​

Answer 1

Step-by-step explanation:

let a/b is a rational no.

put 3√5 = a/b

√5 = a/3b

Therefore,a/b is a rational no.

then a/3b is also a rational no.

and √5 is also equal to a/3b

which is not possible

Therefore,3√5 is an irrational no.

Answer 2

Step-by-step explanation:

let us assume that 3-root5 be rational

3-root5= p/q

3-p/q=root5

3q-p/q=root5

3p-p/q is rational

root5 is alo rational

this contradiction occur because of our wrong assumption

so this contradicts the fact that 3-root5 is irrational