Question

3 root 6× 2-3 root 3× -4 root 2​

Answer 1

$\huge{\pink{6\sqrt{6}+72$

$3 \sqrt{6} (2 - \sqrt{3} )( - 4 \sqrt{2} ) \\ = 6 \sqrt{6} - 3 \sqrt{18} ( - 4 \sqrt{2} ) \\ = 6 \sqrt{6} + 12 \sqrt{36} \\ = 6 \sqrt{6} + 12(6) \\ = 6 \sqrt{6} + 72$