Question

3 + root 7 upon 3 minus root 7 is equal to a + b root 7 find the value of a + b​

Answer 1

Answer:

According to you

3+√7/3-√7=a+b√7

Rationalise the expression

3+√7/3-√7×3+√7/3+√7

(3+√7)^2/(3)^2-(√7)^2

9+7+6√7/9-7

16+6√7/2

8+3√7

=a+b√7

=a=8

=b=3

a+b

8+3

=11

Answer 2

Answer:

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } = a + b \sqrt{7} = >$

$\frac{ {(3 + \sqrt{7})}^{2} }{(3 + \sqrt{7} )(3 - \sqrt{7})} = > \frac{ {(3 + \sqrt{7} )}^{2}}{9 - 7} = >$

${3}^{2} + { (\sqrt{7}) }^{2} + 2 \times 3 \times \sqrt{7} = a + b \sqrt{7}$

=>

16 +6√7 = a+b√7 => a=16 and b=6 So

a+b =>22 Hope it helps you.