Question

3 root 7 x square +4x-root 7=0​

Answer 1

Answer:

Step-by-step explanation:

$3\sqrt{7} x^2+4x-\sqrt{7} =0\\\\3\sqrt{7} x^2+7x-3x-\sqrt{7} =0\\\\\sqrt{7} x(3x+\sqrt{7} )-(3x+\sqrt{7} )=0\\\\(3x+\sqrt{7} )(\sqrt{7} x-1)=0\\\\\bf \Rightarrow x=\frac{1}{\sqrt{7}} , -\frac{\sqrt{7} }{3}$