Question

[3+root2][2-root3][3-root2][2+root3] step by step help me solve his...

Answer 1

Step-by-step explanation:

(3+root2)(2-root3)(3-root2)(2+root3)

(a+b)(a-b)=a^2-b^2

3^2-root^2(2^2-root3^2)

9-2(4-3)

7(1)

7

7 is your ANSWER

Answer 2

Answer:

[3+root2][2-root3][3-root2][2+root3]

[3+root2][3-root2][2-root3][2+root3]

by using identity

[a+b][a-b] = a2-b2

now,[3]2-[root2]2*[2]2-[root3]2

[9-2][4-3] {root2*root2=2,root3*root3=3}

7*1

7

mark me as brainliest