Question

(3/root3 + 1) + (1/root3-1)​

Answer 1

Answer:

here is your answer

Answer 2

Heya mate!!

$\frac{3}{ \sqrt{3} + 1 } + \frac{1}{ \sqrt{3} - 1 } \\ \frac{3}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1} = \frac{3 \sqrt{3} - 3 }{2} \\ \frac{1}{ \sqrt{3} - 1 } \times \frac{ \sqrt{3} + 1}{ \sqrt{3} + 1 } = \frac{ \sqrt{3} + 1}{2} \\ \frac{3 \sqrt{3} - 3 + \sqrt{3} + 1 }{2} = \frac{4 \sqrt{3} - 2 }{2} = 2 \sqrt{3} - 1$

Hope it helps u ✌️✌️