Question

3-root5/3+2 root 5=a root 5-19/11 find a ​

Answer 1

Answer:

(3 - √5) / (3 + 2√5) = a√5 - 19/11

[(3 - 2√5) / (3 - 2√5)][(3 - √5) / (3 + 2√5)] = a√5 - 19/11

[(3 - 2√5)(3 - √5) / (3 - 2√5)(3 + 2√5)] = a√5 - 19/11

(9 - 3√5 - 6√5 + 2 * 5) / (9 + 6√5 - 6√5 - 4 * 5) = a√5 - 19/11

(19 - 9√5) / -11 = a√5 - 19/11

(-19/11) + (-9√5 / -11) = a√5 - 19/11

9√5/11 - 19/11 = a√5 - 19/11

a = 9/11

Step-by-step explanation: