Question

3-root5/3+root5=a root5-bcalculation

Answer 1

Heya

3-√5 / 3+√5

Rationalising the denominator

(3-√5)² / (3+√5)(3-√5)

= 3²-2(3)(√5)+√5² / 3²-√5²

= 9-6√5+24 / 9-5

= 33-6√5 / 4

= -6√5 -(-33) / 4

a = -6/4 = -3/2

b = -33/4

Hope it helps! ^_^

Answer 2

$(3 - \sqrt{5} ) \div (3 + \sqrt{5} )$
on rationalising...

$(3 - \sqrt{5} ) {}^{2} \div 3 {}^{2} - \sqrt{5} {}^{2}$

$9 + 5 - 6 \sqrt{5} \div 9 - 5$

$14 - 6 \sqrt{5} \div 4$
$7 - 3 \sqrt{5} \div 2$
$on \: comparing \: with \: \: \: a \sqrt{5} - b$

a = -3 and b = 7


Thanks