Question

3+ root7/3- root7=a+b root7

Answer 1

Answer:

firstly we rationalise the denominator

3+root7*3+root7/3-root7*3+root7

(3+root7)^2/9-7

then by the property

(a+b)^2=a^2+b^2+2*a*b

3^2+root7^2+2*3*root7/2

9+7 +6root7/2

16+6root7/2

divide 16 and 6by2

8+3root7=a+broot7

a=8

b=3root7