Math, asked by shreyansreddy516, 4 months ago

3.
Rs 650 is to be divided among A, B and C such that 2 times A's share 3 times B's share
and 4tiems C's share are equal. The share of A is....
A)3000
B)300
C)30
D)500
What number must be added to each term of the ratio 37:29 so that it may become 8:7?
D)10
4.
7
102​

Answers

Answered by joelpaulabraham
2

Answer:

3. A's share was Rs.300.

4. 27 must be added to 37 : 29 to get the ratio 8 : 7

Step-by-step explanation:

3.

We know that,

A + B + C = 650

2A = 3B = 4C

So,

2A = 4C

A = 4C/2

A = 2C ----- 1

also,

3B = 4C

B = (4C/3) ----- 2

Now, we also know,

A + B + C = 650 [As Rs.650 divided to each person]

From eq.1 and eq.2, we get,

2C + (4/3)C + C = 650

3C + (4/3)C = 650

Taking LCM = 3

(9C/3) + (4C/3) = 650

(9C + 4C)/3 = 650

13C = 650 × 3

C = 1950/13

C = 150

From eq.1 we get,

A = 2(150)

A = Rs.300

Thus,

A's share was Rs.300.

4.

Let the number to be added be x.

So,

(37 + x) : (29 + x) = 8 : 7

We know that,

Product of extremes = Product of means

7(37 + x) = 8(29 + x)

259 + 7x = 232 + 8x

8x + 232 = 7x + 259

8x - 7x = 259 - 232

x = 27

Hence,

27 must be added to 37 : 29 to get the ratio

8 : 7.

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