Question

3) Running at a constant rate of 6
identical machines can produce total
of 270 bottles per min. At this date
how many bottle could 10 such
machines produce in 4 min.​

Answer 1

Answer:

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

Machines4:3Time(in min.)1:2}::270:x

∴6×1×x=10×4×270⇒x=(10×4×270)(6)⇒x=1800