Question

3.
Sahana drew a rectangle ABCD of which AB=4 cm and BC=6cm. I draw a triangle with
equal area of that rectangle.​

Answer 1

Step-by-step explanation:

Draw AB=4 cm.

2. Construct a perpendicular to AB at B and cut off BC=6 cm.

3. With A as center and 6 cm as radius draw an arc.

4. With C as center and 4 cm as radius draw another arc to intersect the D.

5. Join AD and CD.

Hence, ABCD is the required rectangle .