Question

(3) sec?0 + cosec?0 = sec?0 x cosec²0​

Answer 1

Answer:

Let us consume theta to be "p".

Now proceed.

Given, sin p - cos p = 0

=> (sin p - cos p)² = 0²

=> sin²p + cos²p = 2 sin p cos p

=> 1/2 = sin p cos p

Also, (sin p + cos p)²

= sin²p + cos²p + 2 sin p cos p

= 1 + 2 (1/2)

= 1 + 1

= 2

∴ , (sin p + cos p) = √2

Now, sec p + cosec p = x

=> 1/cos p + 1/sin p = x

=> (sin p + cos p) / sin p cos p = x

=> 2√2 = x