Question

3) (sec A+tan A) (1 - sin A) = ?​

Answer 1

=> ( 1 / cos A + Sin A / Cos A ) ( 1 - Sin A )

=> ( 1 + Sin A / Cos A ) ( 1 - Sin A )

=> 1 - Sin^2 A / Cos A

=> Cos^2 A / Cos A

=> Cos A

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Answer 2

Answer:

Cos A

Step-by-step explanation:

sec A= 1/cos A

tan A= sin A/ cos A

secA + tanA = 1+ sin A / cosA

(1+ sin)(1- sin)= 1- sin^2 = cos^2

cos^2/ cos = cos A