Question

3 sec inverse 1/ x- sin inverse (4x^3-3x)

Answer 1

Answer:

Let x=sinθ⇒sin

−1

x=θ.

Thus we have,

R.H.S.=sin

−1

(3x−4x

3

)=sin

−1

(3sinθ−4sin

3

θ)

=sin

−1

(sin3θ)=3θ=3sin

−1

x

=L.H.S.