3+sec2 theta is equal to
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Answer:
4cosθ−
cosθ
3
=
cosθ
2sinθ
4(1−sin
2
θ)=2sinθ+3
4sin
2
θ+2sinθ−1=0
∴sinθ=
8
−2±
(4+16)
=
8
−2±2
5
=
4
5
−1
,−(
4
5
+1
)
sinθ=sin18
o
i.e, sin(π/10),
∴θ=nπ+(−1)
n
(π/10)
sinθ=−cos36
o
=−sin54
o
=sin(−3π/10)
∴θ=nπ−(−1)
n
(3π/10).
Step-by-step explanation:
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