Question

3 (sec²x + tan²x) = 5

Answer 1

3[sec²x+tan²x]=5
=>3[1+tan²x+tan²x]=5
=>3+2tan²x=5
=>2tan²x=2
=>Tan²x=1
=>Tan²x=tan²π/4
=>X=nπ±π/4
=>x=(n±1)π/4,n E z

Answer 2

3[sec²x+tan²x]=5
=>3[1+tan²x+tan²x]=5
=>3+2tan²x=5
=>2tan²x=2
=>Tan²x=1
=>Tan²x=tan²π/4
=>X=nπ±π/4
=>x=(n±1)π/4,n E z