Question

3. Seven times a two digit number is equal to four times the number obtained by reversing
the order of its digits. If the difference of the digits is 3, determine the number.​

Answer 1

Step-by-step explanation:

First, convert the given data into two equations:

$66x - 33y = 0$

By dividing the whole equation by 33, we get,

$2x - y = 0$

The other equation that we can draw from the data is:

$x - y = 3$

By solving the two equations we get the original number.

Refer the image for a better understanding

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.