3) Shayna left the airport and drove toward the capital at an average speed of 52 km/h. Some time later Mei left driving in the same direction but at an average speed of 65 km/h. After driving for four hours Mei caught up with Shayna. Find the number of hours Shayna drove before Mei caught up.
Answers
Given data : Shayna left the airport and drove toward the capital at an average speed of 52 km/hr. Some time later Mei left driving in the same direction but at an average speed of 65 km/hr. After driving for four hours Mei caught up with Shayna.
To find : The number of hours Shayna drove before Mei caught up.
Solution : According to given data here we know that, Shanaya and Mei covered equal distance.
Let, distance covered by Shanaya and Mei be x km.
- speed of Shanaya = 52 km/hr
- time taken by Shanaya = ?
- speed of Mei = 65 km/hr
- time taken by Mei = 4 hour
Now,
⟹ SPEED = DISTANCE/TIME
⟹ DISTANCE = SPEED * TIME ----{1}
Now,
⟹ Distance covered by Shanaya = Distance covered by Mei
⟹ 52 * Time = 65 * 4 [ from {1} ]
⟹ 52 * Time = 260
⟹ Time = 260/52
⟹ Time = 5 hour
Answer : Shanaya travel 5 hour when caught by Mei.
{More info : conversion hour to second
- Time = 5 hour
- Time = {5 * 60 * 60} sec
- Time = {5 * 3600}
- Time = 18000 sec}
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