Question

3.
Show that
√1+sin A
√1-sin A=
sec A + tan A​

Answer 1

Answer:

this is wrong question

Step-by-step explanation:

there is a mistake

Answer 2

Answer:

LHS = √(1 + sinA)/√(1 - sinA)

= √(1 + sinA) × √(1 + sinA)/√(1 -sinA)×√(1 +sinA)

= √(1 + sinA)²/√(1 -sin²A)

= (1 + sinA)/√cos²A

= (1 + sinA)/cosA

= 1/cosA + sinA/cosA

= secA + tanA = RHS