Question

3. Show that -2 and -5 are the zeroes of the polynomial
${x}^{2}$
+ 7x + 10.

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Answer 1

Step-by-step explanation:

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Answer 2

To show that $-2, \: -5$ are the zeroes of the polynomial ${x}^{2} + 7x + 10$

We plug in these values and verify if the output comes to be $0$.

${( - 2)}^{2} + 7( - 2) + 10$

$4 - 14 + 10 = 0$

Hence, $-2$ is a zero of this polynomial.

${( - 5)}^{2} + 7( - 5) + 10$

$25 - 35 + 10 = 0$

Hence, $-5$ is a zero of this polynomial.