Question

3) Show that 5 √7 is an irrational number.​

Answer 1

Answer:

13.2287565553

Step-by-step explanation:

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Answer 2

Answer:

Let us assume that 5+√7 is a rational number.

= 5+√7 = p/q where p and q are two integers and q=0

= √7 =p/q-5 = p-5q/q

Since,p,q and 5 are integers so,p-5q/q is a rational number.

= √7 is also a rational number.

But this contradicts the fact that √7 is an irrational number.

This contradictions has arisen due to our assumption that 5+√7 is a rational number.

Hence, 5+√7 is an irrational number.