3. Show that one root of the quadratic equation
x + (3 - 2a)x - 6a= 0 is -3. Hence, find its
other root
![x + (3 - 2a)x - 6a = 0 x + (3 - 2a)x - 6a = 0](https://tex.z-dn.net/?f=x+%2B+%283+-+2a%29x+-+6a+%3D+0)
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Answer:
Hope this is helpful
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