Question

3. Show that the point (7,5) is equidistant from the points (2, 4) and (6, 10).​

Answer 1

Answer:

ASSUMPTION:

P(7,5); A(2,4); B(6,10);

Step-by-step explanation:

By using distance formula, we proved that PA=PB, Thus P is equidistant from point A and B.

Answer 2

Answer:

A(x1,y1) A ( x 1 , y 1 ) and B(x2,y2) B ( x 2 , y 2 ) is √(x2−x1)2+(y2−y1)2 ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 .

Step-by-step explanation:

A(x1,y1) A ( x 1 , y 1 ) and B(x2,y2) B ( x 2 , y 2 ) is √(x2−x1)2+(y2−y1)2 ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 . is your answer