Question

3. Show that the roots of the equation x? + px -4 = 0 are real for all real
values of p and a
b
le
are the
of the
date
on​

Answer 1

Answer:

Since D is positive, the roots of the given equation are therefore real.

Step-by-step explanation:

the given equation is:

x^2+px-4=0.

Therefore, D=B^2-4(AC).

i.e. D= p^2-4(1)(-4)

D= p^2+16, which is a positive real number for all real values p and a.

Since our discriminant is positive, we can say that the roots of the given equation are therefore positive.

Hope it helps....:)

Please mark as brainliest cause it's damn correct.